Two Lens

Two lenses, what is the distance between the object and the final image formed by the second lens?

An object is 1.7 meters left of a lens focal length of 0.7 m. A second lens focal length is 0.38 m -2.9 m to the right of the first lens. A) Calculate the distance between the object and the final image formed by the second lens. B) What is the total magnification? C) is the final image real or virtual? d) Is it upright or inverted?

View arbitrators. The key to this type of problem is that 1 (left), eye (middle) of the image is the 2nd (right), object lens. Then using the notation Ref. 1 (+ UN distance of the object to the left of the lens and N + Vn distances itself from the image on the right of the lens N), we initially: U1 = 1.7 m; f1 = 0.7 m, sep = 0.38 m, f2 = -2.9 m, v2 = PD Resolution, v1 = 1 / (1/f1-1 / U1) = U2 = 1.19 m in September-v1 = -0.81 m v2 = 1 / (1/f2-1/u2) = 1.123923 m A. Location of the final image in relation to the subject = v2 + September + U1 = 3.203923 m B. Magnification = v1v2 / (u1u2) = -0.971292 C. Real, as it is to right of the lens 2. D. Invested, from the MAG. is negative.

Two Lens

Two Lens